quant-work-pipe-cistern-theory-part1

Work,Pipes and Cistern

1.A person P1 can finish a job alone in x days and P2 can finish the same job

alone in y days. Then both of them working together can finish the work in

days.

Rajesh and Ajay can complete a job in 25 days and 30 days respectively. Then, both

of them woand Ajay can complete a job in 25 days and 30 days respectively. Then,

both of them wking together can complete the job in = days =15 days

2.Three persons P1, P2 and P3 complete a work in x, y and z days when

working alone. When they work together they can complete the work in:

days.

3.There are three persons P1, P2 and P3 pairwise complete a work i.e. P1 and

P2 working together can complete in x days similarly P2 and P3 in y days and P3

and P1 in z days.

When they work together they can finish the job in days

Suppose three person P1, P2 and P3 pairwise complete a work in 24 days. 20 days

and 30 days respectively. Then when they work together they can complete the work

in days i.e.,16 days

4. A can complete a piece of work in x days working alone, when A and B work

together can complete the work in y days. B alone can finish the work alone in

days.

5. A and B can finish a piece of work in T days. When A working alone takes x

days more than A and B, and B working alone takes y days more than A and B

together.

T =

Example 14 men can do a work in 12 days. If there were 2 men less, in how many

days can they complete one-fourth of the original work?

Solution: Total man-days required to complete the work = 48

th work requires 12 man-days

.

Other Quants Notes:

• Number System
• Average
• Percentages
• Profit & Loss
• Simple and Compound Interest
• Ratio & Proportion
• Partnership
• Mixtures & Allegation
• Time, Speed & Distance
• Work, Pipes & Cistern
• Mensuration
• Geometry
• Height & Distance
• Progression
• Permutation & Combination
• Probability
• Data Interpretation