Work,Pipes and Cistern
1.A person P1 can finish a job alone in x days and P2 can finish the same job
alone in y days. Then both of them working together can finish the work in 
days.
Rajesh and Ajay can complete a job in 25 days and 30 days respectively. Then, both
of them woand Ajay can complete a job in 25 days and 30 days respectively. Then,
both of them wking together can complete the job in = 
days =15 days
days =15 days
2.Three persons P1, P2 and P3 complete a work in x, y and z days when
working alone. When they work together they can complete the work in: 
days.
3.There are three persons P1, P2 and P3 pairwise complete a work i.e. P1 and
P2 working together can complete in x days similarly P2 and P3 in y days and P3
and P1 in z days.
When they work together they can finish the job in 
days
days
Suppose three person P1, P2 and P3 pairwise complete a work in 24 days. 20 days
and 30 days respectively. Then when they work together they can complete the work
in 
days i.e.,16 days
days i.e.,16 days
4. A can complete a piece of work in x days working alone, when A and B work
together can complete the work in y days. B alone can finish the work alone in 
days.
5. A and B can finish a piece of work in T days. When A working alone takes x
days more than A and B, and B working alone takes y days more than A and B
together.
T = 
Example 14 men can do a work in 12 days. If there were 2 men less, in how many
days can they complete one-fourth of the original work?
Solution: Total man-days required to complete the work = 48
th work requires 12 man-days
Other Quants Notes:
