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Number System Quiz-1

Maths is an important subject in CLAT,DULLB & Other Law Exams. In any of law exam, Maths carries weightage of 20 -25 % of questions. With focused practice good marks can be fetched from this section. These questions are very important in achieving your success in CLAT, DULLB and Other Law Exams..

Q1. Which fraction is the greatest among the following:
• All are same
Solution

Since what we can say by seeing 11/32, 15/47, 37/15
11/32 will be equal to 1/3 if 11/33
15/47 will be equal to 1/3 if 15/45
37/115 will be equal to 1/3 if 37/111
So, 11/32 > 1/3 Since 32 < 33
(11/32 > 11/33 = 1/3)
15/47 < 1/3, Since 47 > 45
15/47 < 15/45 = 1/3
37/115 < 1/3, Since 115 > 111
37/115 < 37/111 = 1/3
37/115 < 1/3
Hence 11/32 Will be the greatest

Q2.which fraction is the smallest of the following:

• All are same
•  Solution

, Since
using same principle
Alternate Method:
When the difference of numerator and denominator of all the numbers are same, then choose the one for smallest numerator and denominator.

Q3. What is the remainder if 10400 is divided by
• 0
• 1
• 2
• 3
Solution

Last 3 digits = 400 which is divisible by 8
Q4. A man gave 1/3 of his wealth to his wife, 1/2 of remaining to his first son, 1/2 of remaining to his second son & rest of Rs. 6 lacs to his youngest son. Find out his wealth.
•   40 lacs
• 38 lacs
• 36 lacs
• 42 lacs
Solution

Let wealth be equal to w
Given to wife = w/3
Given to 1st son =
Given to 2nd son =
Youngest son = 6 lac = = w/6
Therefore, w = 36 lac
Alternate Method:
By looking at the question, we can see remaining wealth is 6 lacs and then by looking at the options only 36 and 42 are multiple of 6.
Then, check both the numbers and verify the answer.

Q5. = ?
Solution

=

Q6. The sum of the digits of a two digit number is 8; if the digit are reversed the number is decreased by 54. Find the number
• 71
• 17
• 62
• 53
Solution

x + y = 8
(10x + y) - (10y + x) = 54
9(x - y) = 54,
x - y = 6
Solving this we get, x = 7, y = 1
Alternate Method:
Work through the options

Q7. = ?
• 20
• 30
• 15
• 17
Solution

Since if a + b + c = 0, then a3 + b3 + c3 = 3abc

Q8. = 32 x 32, x = ?
• 230
• 325
• 256
• 125
Solution

= 32 x 32
(64 x 64) x x = (32)2 x (32)2
x = 16 x 16 = 256

Q9. = 0.0008, x = ?
• 30
• 28
• 25
• 40
Solution

= 0.0008, = = 5
x = 25

Q10. Find the greatest number of 4 digits which when divided by 20, 30 &15 leave 18, 28 & 13 as remainders respectively.

• 9958
• 9960
• 9985
• 9990
Solution

LCM of 20, 30 & 15 is 60 highest multiple of 60 less than 10,000 = 9960
Remainder = 18, 28, 13 or 20, 30, 15
20 – 18 = 2, 30 – 28 = 2, 15 – 13 = 2
Hence, number = 9960 - 2 = 9958

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